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Molar Gas Volume

Exam code: 5070
Written by: Ashika|Reviewed by: Caroline Carroll|Updated 2 July 2026

Molar Gas Volumevideo

Molar Gas Volume

Molar Gas Volume

  • Avogadro’s Law states that at the same conditions of temperature and pressure, equal amounts of gases occupy the same volume of space

  • At room temperature and pressure, the volume occupied by one mole of any gas was found to be 24 dm3 or 24,000 cm3

  • This is known as the molar gas volume at RTP

  • RTP stands for “room temperature and pressure” and the conditions are 20 ºC and 1 atmosphere (atm)

  • From the molar gas volume the following formula triangle can be derived:

3-2-1-molar-gas-volume-1

Formula triangle showing the relationship between moles of gas, volume in dm3 and the molar volume

  • If the volume is given in cm3 instead of dm3, then divide by 24,000 instead of 24:

3-2-1-molar-gas-volume-2

Formula triangle showing the relationship between moles of gas, volume in cm3 and the molar volume

  • The formula can be used to calculate the number of moles of gases from a given volume or vice versa

  • Simply cover the one you want and the triangle tells you what to do

To find the volume of a gas

Volume = Moles x Molar Volume

Examples of Converting Moles into Volumes Table

extended_a table, IGCSE & GCSE Chemistry revision notes

To find the moles of a gas

Moles = Volume ÷ Molar Volume

Examples of Converting Volumes into Moles Table

extended_b table, IGCSE & GCSE Chemistry revision notes

Calculating Gas Volumes

Calculating Gas Volumes

  • You may be asked to calculate the volume of a gas from a given amount stated in grams instead of moles

  • To answer these type of questions you must first convert grams to moles and then calculate the volume.

  • A second style of gas calculation involves calculating the volumes of gaseous reactants and products from a balanced equation and a given volume of a gaseous reactant or product

  • These problems are straightforward as you are applying Avogadro's Law, so the moles ( and coefficients) in equations are in the same ratio as the gas volumes